How many digits are required for numbering the pages of a book containing 185 pages?

Pages 1-9 = 9 pages with 1 digit for each number


1 * 9 = 9


Pages 10 - 99 = 90 pages , with 2 digits for each number


2 * 90 = 180


Pages 100 - 185 = 86 pages with 3 digits for each number


3 * 86 = 258





9 + 180 + 258


=447How many digits are required for numbering the pages of a book containing 185 pages?
pages 100 through 185, or 86 pages, need 3 digits so





86 * 3 = 258





Then pages 10 through 99 need 2 digits so





258 + (90 * 2) = 438





then pages 1 through 9 need 1, so





438 + (1 * 9) = 447How many digits are required for numbering the pages of a book containing 185 pages?
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1-digit = 1 * 9 pages = 9 digits


2-digit = 2 * 90 pages = 180 digits


3-digit (100-185) = 3 * 86 pages = 258 digits





TOTAL = 447 digits